PICUP Deflection Function for Two Internal Functions JavaScript Simulation Applet HTML5
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 Parent Category: 04 Waves
 Category: 04 Light
 Created: Monday, 11 June 2018 14:24
 Last Updated: Friday, 20 July 2018 08:48
 Published: Monday, 11 June 2018 14:24
 Written by Fremont
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About
Developed by E. Behringer
Easy JavaScript Simulation by Fremont Teng and Loo Kang Wee
This set of exercises guides the student in exploring primary and secondary rainbows. It requires the student to generate, observe, and describe plots of the deflection angles for light of different wavelengths and identify rainbow angles for different values of the relative index of refraction.
Subject Area  Waves & Optics 

Levels  First Year and Beyond the First Year 
Available Implementation  Python & Easy JavaScript Simulation 
Learning Objectives 
Students who complete this set of exercises will be able to

Time to Complete  120 min 
This set of exercises may be used in an introductory course that covers optics or in an upperlevel optics course. The first three computational exercises are not demanding, but collectively provide an opportunity to deduce physical consequences (e.g., why is it that the primary and secondary rainbows are bright in particular directions). The last exercise is intended purely as a crude, ‘zeroeth order’ estimate of the irradiance as a function of deflection angle, purposefully neglecting polarization effects. Additional computational exercises have been described by D.S. Amundsen et al., Am. J. Phys. 77 (9), 795798 (2009). An experimental apparatus to explore rainbows up to the 6th order has been described by G. Casini and A. Covello, Am. J. Phys. 80 (11), 10271034 (2012).
For Exercises 3 and 4, the theoretical concepts required are the Law of Refraction and the Law of Reflection, which are standard topics in introductory courses and are usually revisited in intermediate or advanced optics courses.
For Exercise 5, the crude model is nothing more than summing the irradiances associated with different rays, which implicitly assumes that the rays are incoherent with one another. Depending on the course, this can be contrasted with the ideas underlying the derivation of far field diffraction patterns  namely, that one works with the electric fields and carefully accounts for the relative phases of contributions from different parts of an extended source.
EXERCISE 1: OBTAIN AND USE INFORMATION FROM PEERREVIEWED LITERATURE
Water and air are the two materials involved with producing rainbows we may see in the sky after a thunderstorm. To accurately predict where rainbows will appear, we need to have accurate information about the refractive indices of water and air.
(a) Obtain a copy of “Models for the wavelength dependence of the index of refraction of water”, Applied Optics 36 (16), 37853787 (1997) by Paul D.T. Huibers, and use Eq. (3) of that paper to generate a plot of the refractive index of water as a function of wavelength in the range from 400 to 650 nm.
(b)
Obtain a copy of “Refractive index of air: new equations for the visible
and near infrared”, Applied Optics 35(9),
15661573 (1996) by Philip E. Ciddor, and use Eq. (1) of that paper to
generate a plot of
Which material has the larger change in refractive index over the wavelength range from 400 to 650 nm? Calculate the ratio of the larger change to the refractive index of the material for a wavelength of 400 nm, and comment on the magnitude of the ratio.
EXERCISE 2: DEFLECTION ANGLE FOR A LIGHT RAY ENTERING A SPHERICAL RAINDROP
Assume
that a light ray incident on a spherical raindrop at an angle
`
Show
that if
The
deflection angle
EXERCISE 3: COMPUTE THE DEFLECTION ANGLE VERSUS INCIDENT ANGLE
Generate
a plot of the deflection angle
Near
the minimum of the deflection function (that is, the
EXERCISE 4: WHERE IS THE SECONDARY (DOUBLE) RAINBOW?
Repeat the computation of Exercise 3, but now assume that the ray undergoes two internal reflections within the raindrop. In this case, show that the deflection angle is given by
and plot the deflection angle versus the incident angle for rays of wavelength 400 nm and 650 nm. The two curves should have minima that are close to each other, but not identical. What are the values of the incident angle corresponding to these two minima? Assuming that these minima correspond to the rainbow direction, what direction do you have to look relative to the horizontal to see the bright red band of the secondary rainbow? Can a ground based observer see these rays? Do the rays that produce the secondary rainbow enter the top of the raindrop? What direction do you have to look relative to the horizontal to see the bright violet band? Which band appears higher in the sky?
Near
the minimum of the deflection function (that is, the
EXERCISE 5: CRUDE ESTIMATE OF THE IRRADIANCE VERSUS DEFLECTION ANGLE FOR A SINGLE WAVELENGTH: PRIMARY RAINBOW
Assume
that the each outgoing ray produces an irradiance that is equal to
EXERCISE 5: CRUDE ESTIMATE OF THE IRRADIANCE VERSUS DEFLECTION ANGLE FOR A SINGLE WAVELENGTH: PRIMARY RAINBOW
Assume that the each outgoing ray produces an irradiance that is equal to where here the angles are assumed to be in degrees and the implied width of this distribution is . (For simplicity, we neglect the loss of intensity during refraction and internal reflection. This is a huge oversimplification, but it allows us to focus on adding up contributions from each ray.) Sum up the contributions from rays uniformly distributed over the scaled impact parameter to compute the overall irradiance as a function of deflection angle for light of wavelength 400 nm. Plot the resulting irradiance distribution versus deflection angle for a single wavelength. How does this plot help explain why the rainbow is bright?
#
# Rainbows_Exercise_5.py
#
# Plot the irradiance as a function of
# deflection angle for rays undergoing
# a single internal reflection,
# assuming a spherical water drop
# and two wavelengths.
#
# Here, as a 'zeroeth' approximation,
# the Fresnel coefficients are NOT taken into account.
#
# The refractive index of water is taken from
# Eq. 3 of P.D.T Huibers, Applied Optics,
# Vol. 36, No. 16, pp. 37853787 (1997).
#
# The refractive index of air is taken from
# Eq. 1 of P.E. Ciddor, Applied Optics,
# Vol. 35, No. 9, pp. 15661573 (1996).
#
# Written by:
#
# Ernest R. Behringer
# Department of Physics and Astronomy
# Eastern Michigan University
# Ypsilanti, MI 48197
# (734) 4878799
# This email address is being protected from spambots. You need JavaScript enabled to view it.
#
# 20160109 by ERB
#
from __future__ import print_function
from pylab import figure,plot,xlim,xlabel,ylim,ylabel,grid,legend,title,show
from math import pi,asin
from numpy import linspace,arcsin,sin,exp,zeros,argmin,argmax
# Define the index of refraction function for water
def water_index(wavelength):
n_H2O = 1.31279 + 15.762/wavelength  4382.0/(wavelength**2) + 1.1455e6/(wavelength**3)
return(n_H2O)
# Define the index of refraction function for air
# Note: wavelength is supposed to be in micrometers
def air_index_minus_one(wavelength):
term1 = 0.05792105/(238.0185  1.0e6/(wavelength**2))
term2 = 0.00167917/(57.362  1.0e6/(wavelength**2))
return(term1+term2)
# Inputs
wavelength_r = 650 # vacuum wavelength in nm ("red")
wavelength_v = 400 # vacuum wavelength in nm ("violet")
n_r = water_index(wavelength_r) # refractive index of water at wavelength_r
n_v = water_index(wavelength_v) # refractive index of water at wavelength_v
npts = 801 # the number of scaled impact parameters, i.e., rays
width = 1.0 # angular width of ray [deg]
ndetpts = 501 # the number of detector points
n_ar = 1.0 + air_index_minus_one(wavelength_r) # refractive index of air at wavelength_r
n_av = 1.0 + air_index_minus_one(wavelength_v) # refractive index of air at wavelength_v
# Generate the array of uniformly distributed scaled impact parameters
scaled_b = linspace(0.0,1.0,npts)
# Generate the corresponding array of incident angle values [rad]
theta_i = arcsin(scaled_b)
# Generate the corresponding array of incident angle values [deg]
theta_i_deg = 180.0*theta_i/pi
# Set up the arrays of deflection angles
theta_r = zeros(npts)
theta_v = zeros(npts)
# Calculate the refraction angle for each incident angle
# and for red and for violet light
for j in range(0,npts):
theta_r[j] = asin((n_ar/n_r)*sin(theta_i[j]))
theta_v[j] = asin((n_av/n_v)*sin(theta_i[j]))
# Calculate the deflection angle for each incident angle for red light
theta1r = 2.0*(theta_i  theta_r) + 1.0*(pi  2.0*theta_r) # First deflection function
theta1r_deg = theta1r*180.0/pi
# Calculate the deflection angle for each incident angle for violet light
theta1v = 2.0*(theta_i  theta_v) + 1.0*(pi  2.0*theta_v) # First deflection function
theta1v_deg = theta1v*180.0/pi
print("The primary rainbow deflection angle for red light is ",min(theta1r_deg))
# The index of this value is
index_r = argmin(theta1r_deg)
print("This primary rainbow deflection angle for red light corresponds to")
print("an incident angle of ",theta_i_deg[index_r]," deg.")
print("The red band of the primary rainbow appears at ",180.0min(theta1r_deg)," above the horizontal.")
print(" ")
print("The primary rainbow deflection angle for violet light is ",min(theta1v_deg))
# The index of this value is
index_v = argmin(theta1v_deg)
print("This primary rainbow deflection angle for violet light corresponds to")
print("an incident angle of ",theta_i_deg[index_v]," deg.")
print("The violet band of the primary rainbow appears at ",180.0min(theta1v_deg)," above the horizontal.")
print(" ")
# Set up the array of irradiance versus deflection angle
deflection_angles_deg = linspace(130,180,ndetpts)
irradiance_r = zeros(ndetpts)
irradiance_v = zeros(ndetpts)
# Accummulate irradiance from each ray
# that corresponds to one impact parameter
for i in range(0,ndetpts):
# for every detection angle...
for j in range(0,npts):
# accumulate the irradiance into a particular angle from each ray
irradiance_r[i] = irradiance_r[i] + exp(((deflection_angles_deg[i]  theta1r_deg[j])/width)**2)
irradiance_v[i] = irradiance_v[i] + exp(((deflection_angles_deg[i]  theta1v_deg[j])/width)**2)
# Scale the intensities
scaled_irradiance_r = irradiance_r/max(irradiance_r)
scaled_irradiance_v = irradiance_v/max(irradiance_v)
# The index of this value at which the maximum scaled irradiance occurs is
index_r_irradiance = argmax(scaled_irradiance_r)
print("The detection angle at which ")
print("the red irradiance is maximum = ",deflection_angles_deg[index_r_irradiance]," deg.")
print("The maximum appears ",180.0deflection_angles_deg[index_r_irradiance], " deg. above the horizontal.")
print(" ")
# The index of this value is
index_v_irradiance = argmax(scaled_irradiance_v)
print("The detection angle at which ")
print("the violet irradiance is maximum = ",deflection_angles_deg[index_v_irradiance]," deg.")
print("The maximum appears ",180.0deflection_angles_deg[index_v_irradiance], " deg. above the horizontal.")
print(" ")
#
# Start a new figure. This will be a plot of the
# scaled irradiance versus deflection angles
figure()
# Set the limits of the horizontal axis
xlim(130,180)
# Label the horizontal axis
xlabel("Detection angle relative to incident ray \(\\phi\) [deg]", size = 16)
# Set the limits of the vertical axis
ylim(0.0,1.0)
# Label the vertical axis
ylabel("Scaled irradiance \(I/I_{max}\)", size = 16)
# Draw a grid
grid(True)
# Plot the deflection functions
plot(deflection_angles_deg,scaled_irradiance_r,"r",label="\(\lambda = 650 \\, {\\rm nm}\)")
plot(deflection_angles_deg,scaled_irradiance_v,"b",label="\(\lambda = 400 \\, {\\rm nm}\)")
# Generate the legend
legend(loc=1)
# Generate the title
title("Crude estimate of irradiance versus deflection angle\n for one internal reflection")
show()
Exercise 1: Obtain and use information from peerreviewed literature
The plot for the refractive index of water should look like:
`
The plot for the deviation of the refractive index of air from unity should look like:
Exercise 2: Deflection angle for a light ray entering a spherical raindrop
To calculate the deflection angle, one needs to know the refractive index of the air and the water at the particular wavelength and also the angle of incidence of the incoming ray. The laws of refraction and reflection are then applied to obtain the angles of refraction and the angle of reflection for the internal reflection. Students should be able to show that the equalities shown in the figure illustrating the ray/raindrop geometry.
Exercise 3: Compute the deflection angle versus incident angle
The solution for Exercise 3 is:
The
minimum of the deflection function for
Exercise 4: Where is the double (secondary) rainbow?
The solution for Exercise 4 is:
The
minimum of the deflection function for
Exercise 5: Crude estimate of the irradiance versus deflection angle for a single wavelength: Primary Rainbow
The solution for Exercise 5 is:
Note
that irradiance is distributed over a large range of detection angles, and that the irradiance has a peak near (but not at) the minimum of the deflection function for these chosen parameters. If we use an angular width smaller than
Most introductory textbooks mention rainbows and the angles at which they can be observed, but do not necessarily explain why rainbows are bright. This set of exercises is intended to show how irradiance “piles up” around the minima of the deflection functions calculated in Exercises 3 and 4.
Translations
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Software Requirements
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with best with  Chrome  Chrome  Chrome  Chrome 
support fullscreen?  Yes. Chrome/Opera No. Firefox/ Samsung Internet  Not yet  Yes  Yes 
cannot work on  some mobile browser that don't understand JavaScript such as.....  cannot work on Internet Explorer 9 and below 
Credits
Fremont Teng; Loo Kang Wee
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Sample Learning Goals
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For Teachers
Deflection Function for Two Internal Functions JavaScript Simulation Applet HTML5
Instructions
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Research
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Video
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Version:
 https://www.compadre.org/PICUP/exercises/exercise.cfm?I=129&A=rainbows
 http://weelookang.blogspot.com/2018/06/deflectionfunctionfortwointernal.html
Other Resources
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