About
Developed by E. Behringer
This set of exercises guides the students to compute and analyze the behavior of a charged particle in a spatial region with mutually perpendicular electric and magnetic fields. It requires the student to determine the Cartesian components of hte forces acting on the particle and to obtain the corresponding equations of motion. The solutions to these equations are obtained through numerical integation, and the capstone exercise is the simulation of the $\overrightarrow{E}\times \overrightarrow{B}$ (Wien) filter.
Subject Area  Electricity & Magnetism 

Levels  First Year and Beyond the First Year 
Available Implementation  Python 
Learning Objectives 
Students who complete this set of exercises will be able to:

Time to Complete  120 min 
EXERCISE 4: THE $\overrightarrow{E}\times \overrightarrow{B}$ (WIEN) FILTER, PART 2
As an extension of Exercise 3, now assume that the particles entering the field region at the origin have a normal distribution of velocities directed purely along the $z$axis. The center of the distribution is ${v}_{z,pass}$ and its width is $0.1{v}_{z,pass}$.
(a) Allow $40,000$ particles from this distribution to enter the field region at the origin. What is the resulting histogram of the scaled velocities ${v}_{z}/{v}_{z,pass}$ of the particles transmitted through a circular aperture of radius $R=1.0$ mm centered on the $z$axis? How does it compare to the histogram of the initial velocities?
(b) Repeat part (a) for an aperture of radius $R=0.5$ mm.
It is worth noting that an actual source of ions will not only be characterized by a distribution of velocities, but also distribution of directions (no ion beam is strictly monodirectional, just like a laser beam is not strictly monodirectional). This is an additional fact that would have to be considered to accurately simulate the performance of a real Wien filter.
#
# ExB_Filter_Exercise_4.py
#
# This file is used to numerically integrate
# the second order linear differential equations
# that describe the trajectory of a charged particle through
# an E x B velocity filter.
#
# Here, it is assumed that the axis of the filter
# is aligned with the zaxis, that the magnetic field
# is along the +xdirection, and that the electric field
# is along the ydirection.
#
# The numerical integration is done using the builtin
# routine odeint.
#
# Many particles selected from a normal distribution of
# zvelocities are sent through the filter and histograms
# of the zvelocities of the incident and transmitted particles
# are produced.
#
# By:
# Ernest R. Behringer
# Department of Physics and Astronomy
# Eastern Michigan University
# Ypsilanti, MI 48197
# (734) 4878799 (Office)
# This email address is being protected from spambots. You need JavaScript enabled to view it.
#
# Last updated:
#
# 20160624 ERB
#
from pylab import figure,xlim,xlabel,ylim,ylabel,grid,title,hist,show,text
from numpy import sqrt,array,arange,random,absolute,zeros,linspace
from scipy.integrate import odeint
#
# Initialize parameter values
#
q = 1.60e19 # particle charge [C]
m = 7.0*1.67e27 # particle mass [kg]
KE_eV = 100.0 # particle kinetic energy [eV]
Ex = 0.0 # Ex = electric field in the +x direction [N/C]
Ey = 105.0 # Ey = electric field in the +y direction [N/C]
Ez = 0.0 # Ez = electric field in the +z direction [N/C]
Bx = 0.002 # Bx = magnetic field in the +x direction [T]
By = 0.0 # By = magnetic field in the +x direction [T]
Bz = 0.0 # Bz = magnetic field in the +x direction [T]
R_mm = 0.5 # R = radius of the exit aperture [mm]
L = 0.25 # L = length of the crossed field region [mm]
Ntraj = 40000 # number of trajectories
transmitted_v = zeros(Ntraj) # array to save velocities of transmitted particles
n_transmitted = 0 # counter for the number of transmitted particles
# Derived quantities
qoverm = q/m # charge to mass ratio [C/kg]
KE = KE_eV*1.602e19 # particle kinetic energy [J]
vmag = sqrt(2.0*KE/m) # particle velocity magnitude [m/s]
R = 0.001*R_mm # aperture radius [m]
vzpass = Ey/Bx # zvelocity for zero deflection [m/s]
# Set up the distribution of incident velocities
mean = vzpass # the mean of the velocity distribution is vzpass
sigma = 0.1*vzpass # the width of the velocity distribution is 0.1*vzpass
vz = mean + sigma*random.randn(Ntraj) # the set of initial velocity magnitudes
scaled_vz = vz/vzpass # the set of scaled initial velocity magnitudes
# Set up the bins for the histograms
scaled_vz_min = 0.6
scaled_vz_max = 1.4
Nbins = 64
scaled_vz_bins = linspace(scaled_vz_min,scaled_vz_max,Nbins+1)
vz_bins = vzpass*scaled_vz_bins
#
# Over what time interval do we integrate?
#
tmax = L/vzpass;
#
# Specify the time steps at which to report the numerical solution
#
t1 = 0.0 # initial time
t2 = tmax # final scaled time
N = 1000 # number of time steps
h = (t2t1)/N # time step size
# The array of time values at which to store the solution
tpoints = arange(t1,t2,h)
# Specify initial conditions that don't change
x0 = 0.0 # initial xcoordinate of the charged particle [m]
dxdt0 = 0.0 # initial xvelocity of the charged particle [m/s]
y0 = 0.0 # initial ycoordinate of the charged particle [m]
dydt0 = 0.0 # initial yvelocity of the charged particle [m/s]
z0 = 0.0 # initial zcoordinate of the charged particle [m]
#
# Here are the derivatives of position and velocity
def derivs(r,t):
# derivatives of position components
xp = r[1]
yp = r[3]
zp = r[5]
dx = xp
dy = yp
dz = zp
# derivatives of velocity components
ddx = qoverm*(Ex + yp*Bz  zp*By)
ddy = qoverm*(Ey + zp*Bx  xp*Bz)
ddz = qoverm*(Ez + xp*By  yp*Bx)
return array([dx,ddx,dy,ddy,dz,ddz],float)
# Start the loop over the initial velocities
for i in range (0,Ntraj1):
# Specify initial conditions
dzdt0 = vz[i] # initial zvelocity of the charged particle [m/s]
r0 = array([x0,dxdt0,y0,dydt0,z0,dzdt0],float)
# Calculate the numerical solution using odeint
r = odeint(derivs,r0,tpoints)
# Extract the 1D matrices of position values
position_x = r[:,0]
position_y = r[:,2]
position_z = r[:,4]
# Extract the 1D matrices of velocity values and final velocity
v_x = r[:,1]
v_y = r[:,3]
v_z = r[:,5]
vxf = v_x[N1]
vyf = v_y[N1]
vzf = v_z[N1]
vf = sqrt(vxf*vxf + vyf*vyf + vzf*vzf)
# If the particle made it through the aperture, save the velocity
if absolute(position_x[N1]) < R:
if absolute(position_y[N1]) < sqrt(R*R  position_x[N1]*position_x[N1]):
transmitted_v[n_transmitted] = vf
n_transmitted = n_transmitted + 1
# Only save the nonzero values for the histogram
transmitted_v_f = transmitted_v[0:n_transmitted]
scaled_transmitted_v_f = transmitted_v_f/vzpass
# Let the user know how many particles were transmitted
print("The number of incident particles is %d"%Ntraj) #Frem: Added Brackets
print("The number of transmitted particles is %d"%n_transmitted) #Frem: Added Brackets
# start a new figure
figure()
# plot the histogram of scaled initial velocities
n, bins, patches = hist(scaled_vz, scaled_vz_bins, normed=0, facecolor='orange', alpha=0.75)
xlabel('\(v_z/v_{z,pass}\) [m/s]',size = 16)
ylabel('\(N\)',size = 16)
title('Histogram of initial \(v_z/v_{z,pass}\) values')
xlim(scaled_vz_min,scaled_vz_max)
ylim(0,0.075*Ntraj)
grid(True)
show()
# start a new figure
figure()
# plot the histogram of scaled final velocities (transmitted particles)
n, bins, patches = hist(scaled_transmitted_v_f, scaled_vz_bins, normed=0, facecolor='purple', alpha=0.75)
xlabel('\(v_z/v_{z,pass}\)',size = 16)
ylabel('\(N\)',size = 16)
title('Histogram of \(v_z/v_{z,pass}\) values for transmitted particles')
xlim(scaled_vz_min,scaled_vz_max)
ylim(0,0.075*Ntraj)
grid(True)
text(0.65,2750,"R = %.2f mm"%R_mm,size=16)
show()
Translations
Code  Language  Translator  Run  

Software Requirements
Android  iOS  Windows  MacOS  
with best with  Chrome  Chrome  Chrome  Chrome 
support fullscreen?  Yes. Chrome/Opera No. Firefox/ Samsung Internet  Not yet  Yes  Yes 
cannot work on  some mobile browser that don't understand JavaScript such as.....  cannot work on Internet Explorer 9 and below 
Credits
Fremont Teng; Loo Kang Wee
end faq
Sample Learning Goals
[text]
For Teachers
[text]
Research
[text]
Video
[text]
Version:
 https://www.compadre.org/PICUP/exercises/Exercise.cfm?A=ExB_Filter&S=6
 http://weelookang.blogspot.com/2018/06/wienexbfilterexercise123and4.html
Other Resources
[text]
end faq
Testimonials (0)
There are no testimonials available for viewing. Login to deploy the article and be the first to submit your review!
You have to login first to see this stats.